Scala print items in list

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WebApr 13, 2024 · In Scala, list is defined under scala.collection.immutable package. A list is a collection of same type elements which contains immutable data. There are multiple … WebFeb 11, 2013 · 2 Answers Sorted by: 45 You can use pattern matching: val hd::tail = List (1,2,3,4,5) //hd: Int = 1 //tail: List [Int] = List (2, 3, 4, 5) Or just .head/.tail methods: val hd = foo.head // hd: Int = 1 val hdOpt = foo.headOption // hd: Option [Int] = Some (1) val tl = foo.tail // tl: List [Int] = List (2, 3, 4) Share Improve this answer Follow

Find the last element of a list in scala - GeeksforGeeks

WebPrint values of items in a list object Demo { def main(args: Array[String]) { val name_seq = Seq("eduCBA", "is", "good") val num_seq = Seq(1, 2, 3) for ( item <- name_seq) println( item) for (item <- num_seq) { println( item); } } } Output: Explanation: The output consists of print statements from 2 loop executions. Webyou can print each string like this: for (name <- names) println (name) This is what it looks like in the REPL: scala> for (name <- names) println (name) Joel Chris Ed A great thing … landscaping around vinyl fence

How to create all possible combinations from the elements of a list?

WebApr 16, 2015 · scala> val l = List ("a", "b", "c") scala> l.lift (1) Some ("b") scala> l.lift (5) None Whenever you're performing an operation that may fail in this way it's great to use an Option and get the type system to help make sure you are handling the case where the element doesn't exist. Explanation: WebHere is the documentation from scala: def -- [B >: A] (that: List [B]) : List [B] Computes the difference between this list and the given list that. that the list of elements to remove from this list. returns this list without the elements of the given list that. deprecated: use list1 filterNot (list2 contains) instead WebSyntax of Scala List In Scala, we can create a list in two ways We can assign value to the list while creating the list object without defining the data type. We can also create a list with data type declaration with it so only that type of data we can assign to a specific list later. hemiresektion nach bowers

Iterate over list indexes and values, in Scala - Programming Idioms

WebJul 14, 2014 · Try this: val dup = List(1,1,1,2,3,4,5,5,6,100,101,101,102) dup.groupBy(identity).collect { case (x, List(_,_,_*)) => x } The groupBy associates each distinct integer with a list of its occurrences. The collect is basically map where non-matching elements are ignored. The match pattern following case will match integers x … WebNov 5, 2024 · In Scala a List is immutable. It must be copied each time we want to modify something. This makes some operations (like appending) slower. But Immutability has many advantages. To copy a list, can just reuse an existing list, as it will never change. And There are known security benefits to immutable objects. hemi red eyeWebFeb 10, 2016 · 1 - Declare your List val myCharList: List [Char] = List (' (',')',' (',')') 2 - Define your method def printList ( chars: List [Char] ): Boolean = { if ( chars.isEmpty ) true //every item of the list has been printed else { println ( chars.head ) printList ( chars.tail ) } } 3 - Call the … hemi receiver lighting

"WebUsing the Set force the list to have unique values: def maxes2 [A] (n:Int) (l:Traversable [A]) (implicit o:Ordering [A]) = l.foldLeft (List.empty [A]) { (xs,y) => import o._ if (xs.size < n) (y::xs).sort (lt _) else { val first = xs.head if (first < y) (y:: (xs - first)).sort (lt _) else xs } } Share Improve this answer " - Scala print items in list

Scala print items in list

WebJan 25, 2011 · scala> val data =List ( ("2001",13.1), ("2009",3.1), ("2004",24.0), ("2011",1.11)) data: List [ (java.lang.String, Double)] = List ( (2001,13.1), (2009,3.1), (2004,24.0), (2011,1.11)) scala> data.foreach (x => println (x._1+" "+x._2)) 2001 13.1 2009 3.1 2004 24.0 2011 1.11 Share Improve this answer Follow answered Jan 25, 2011 at 12:17 WebIf you still want to use list there are a few ways to prepend an item to the list. What you can do is (yes the top part is still wrong): scala> var outList : List[String] = Nil outList: List[String] = List() scala> val strArray = Array("a","b","c") strArray: Array[java.lang.String] = Array(a, b, c) scala> for(s <- strArray) outList = outList ...

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WebJul 18, 2024 · 20 In scala foreach loop if I have list val a = List ("a","b","c","d") I can print them without a pattern matching like this a.foreach (c => println (c)) But, if I have a tuple like this val v = Vector ( (1,9), (2,8), (3,7), (4,6), (5,5)) why should I have to use v.foreach { case (i,j) => println (i, j) } a pattern matching case { brackets WebJan 11, 2024 · You can just do: def printNTimes (items: List [Int], n: Int): List [Int] = { items.flatMap (i => Vector.fill (n) (i)) } or: def printNTimes (items: List [Int], n: Int): List [Int] = { items.flatMap (Vector.fill (n) (_)) } Then running: println (printNTimes (List (1,2,4), 3)) will output: List (1, 1, 1, 2, 2, 2, 4, 4, 4) Share Improve this answer

WebFind many great new & used options and get the best deals for MILAN ITALY PHOTOGRAPH PIAZZA DELLA SCALA, GALLERIA LARGE ALBUMEN PRINT 1870s at the best online prices at eBay! Free shipping for many products! WebApr 20, 2011 · As in Scala 2.11.7 the following are valid: scala> val xs = List (1,2,3,4) xs: List [Int] = List (1, 2, 3, 4) 1) Zip the tail scala> xs.zip (xs.tail) res0: List [ (Int, Int)] = List ( (1,2), (2,3), (3,4)) 2) Slide the window scala> xs.sliding (2) res1: Iterator [List [Int]] = non-empty iterator Share Improve this answer Follow

WebJun 22, 2024 · Here, we will create a list of integers using List collection. Then we will print items of the List collection except the head item using the tail property on the console … WebFeb 28, 2024 · Lambda Expression in Scala. Lambda Expression refers to an expression that uses an anonymous function instead of variable or value. Lambda expressions are more convenient when we have a simple function to be used in one place. These expressions are faster and more expressive than defining a whole function. We can make our lambda …

WebMar 14, 2024 · In a Scala list, each element must be of the same type. The implementation of lists uses mutable state internally during construction. In Scala, list is defined under …

WebJul 15, 2013 · If you use list instead, toString () method prints the actual elenents (not the hashCode) var a = List (1,2,3) println (a) or var a = Array (1,2,3) println (a.toList) Share Improve this answer Follow answered Jul 13, 2013 … hemi retinal vein occlusion icd 10 codeWebMar 31, 2024 · Without using loops: * symbol is use to print the list elements in a single line with space. To print all elements in new lines or separated by comma use sep=”\n” or sep=”, ” respectively. hemi ram performance partsWebScala tuple combines a fixed number of items together so that they can be passed around as a whole. Unlike an array or list, a tuple can hold objects with different types but they are also immutable. The following is an example of a tuple holding an integer, a string, and the console. val t = (1, "hello", Console) Which is syntactic sugar ... landscaping around swimming pool ideasWebJan 20, 2024 · 1. The map method in Scala: you're using map, which expects a function with no side-effects (printing is a side effect). What you're looking for is: l.toStream.foreach (x … hemi resurfacing arthroplastyWebFeb 5, 2024 · import java.nio.file.Paths println (Paths.get (".").toAbsolutePath) Remark on scala.reflect.io.File: I don't see any reason to look into scala.reflect packages for such mundane tasks. Getting the current working directory has usually nothing to do with Scala's reflection capabilities. Here are more reasons not to use scala.reflect.io.File: link. hemi resurfacing shoulderWebScala - Lists Previous Page Next Page Scala Lists are quite similar to arrays which means, all the elements of a list have the same type but there are two important differences. First, lists are immutable, which means elements of a list cannot be changed by assignment. Second, lists represent a linked list whereas arrays are flat. hemi-retinal vein occlusionWebOct 28, 2012 · You'll have to convert your list to a set first though. scala> List (1,2,3).toSet [Int].subsets.map (_.toList).toList res9: List [List [Int]] = List (List (), List (1), List (2), List (3), List (1, 2), List (1, 3), List (2, 3), List (1, 2, 3)) Share Improve this answer Follow edited Oct 28, 2012 at 17:53 answered Oct 28, 2012 at 15:00 Kim Stebel he mir flickr retrieval evaluation